Which of the following is the correct method to copy a binary file without applying templates in Yeoman?

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Multiple Choice

Which of the following is the correct method to copy a binary file without applying templates in Yeoman?

Explanation:
When you need to duplicate a binary file in a Yeoman generator without applying any template processing, you should copy the file as-is using this.fs.copy. The copy operation transfers the file’s bytes without interpreting or replacing placeholders, so the binary data remains intact. In contrast, the template-aware method (copyTpl) would try to render EJS-like templates inside the file, which can corrupt binary data. Writing manually would require you to supply the exact content, which isn’t appropriate for a direct binary copy. Therefore, this.fs.copy is the correct approach.

When you need to duplicate a binary file in a Yeoman generator without applying any template processing, you should copy the file as-is using this.fs.copy. The copy operation transfers the file’s bytes without interpreting or replacing placeholders, so the binary data remains intact. In contrast, the template-aware method (copyTpl) would try to render EJS-like templates inside the file, which can corrupt binary data. Writing manually would require you to supply the exact content, which isn’t appropriate for a direct binary copy. Therefore, this.fs.copy is the correct approach.

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